Light of intensity 10^{-10} W/m^2 and wavele | vedclass

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(C) The intensity $I$ is given by $I = \frac{P}{A}$,where $P$ is the power and $A$ is the area.Power $P = I 	imes A = \frac{nhc}{t\lambda}$,where $n$

Vedclass · Accepted Answer

$300$

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(C) The intensity $I$ is given by $I = \frac{P}{A}$,where $P$ is the power and $A$ is the area.Power $P = I 	imes A = \frac{nhc}{t\lambda}$,where $n$ is the number of photons,$h$ is Planck's constant,$c$ is the speed of light,and $t$ is time.Rearranging for the number of photons per second $(n/t)$:$\frac{n}{t} = \frac{IA\lambda}{hc}$Substituting the given values:$\frac{n}{t} = \frac{10^{-10} 	imes 10^{-6} 	imes 5.6 	imes 10^{-7}}{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}$$\frac{n}{t} \approx \frac{5.6 	imes 10^{-23}}{19.89 	imes 10^{-26}} \approx 0.2815 	imes 10^3 \approx 281.5$Rounding to the nearest provided option,the number of photons is $300$.

Light of intensity $10^{-10} \ W/m^2$ and wavelength $5.6 \times 10^{-7} \ m$ is incident on a surface of area $10^{-6} \ m^2$. What is the number of photons incident per second?

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