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(C) According to the law of conservation of linear momentum,since the initial mass $M$ is stationary,the total initial momentum is $0$.Therefore,the t

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(C) According to the law of conservation of linear momentum,since the initial mass $M$ is stationary,the total initial momentum is $0$.Therefore,the two fragments must move in opposite directions with equal magnitudes of momentum: $p_1 = p_2 = p$.The de Broglie wavelength is given by the formula $\lambda = \frac{h}{p}$.Since both fragments have the same magnitude of momentum $p$,their de Broglie wavelengths will be $\lambda_1 = \frac{h}{p}$ and $\lambda_2 = \frac{h}{p}$.Thus,the ratio of their de Broglie wavelengths is $\frac{\lambda_1}{\lambda_2} = \frac{h/p}{h/p} = 1$.

$A$ stationary mass $M$ splits into two fragments of masses $m_1$ and $m_2$. What is the ratio of their de Broglie wavelengths,${\lambda _1}/{\lambda _2}$?

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