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(A) The energy required to remove the first electron from a helium atom $(He)$ is given as $E_1 = 24.6 \, eV$.After the first electron is removed,the

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$79$

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(A) The energy required to remove the first electron from a helium atom $(He)$ is given as $E_1 = 24.6 \, eV$.After the first electron is removed,the remaining species is a $He^+$ ion,which is a hydrogen-like system with atomic number $Z = 2$.The energy required to remove the second electron from the ground state of $He^+$ is given by the formula $E_n = 13.6 	imes Z^2 \, eV$.For $He^+$,$Z = 2$,so $E_2 = 13.6 	imes (2)^2 = 13.6 	imes 4 = 54.4 \, eV$.The total energy required to remove both electrons is the sum of the energy required for the first and second ionization: $E_{total} = E_1 + E_2 = 24.6 \, eV + 54.4 \, eV = 79 \, eV$.

The energy required to remove one electron from a helium atom is $24.6 \, eV$. What is the energy required to remove both electrons from the helium atom (in $, eV$)?

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