The potential barrier of a P-N junction is 0. | vedclass

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(A) The electric field $E$ in a depletion layer is given by the relation $E = \frac{V}{d}$,where $V$ is the potential barrier and $d$ is the thickness

Vedclass · Accepted Answer

$1.0 	imes 10^6 \ V/m$

Vedclass · Answer

(A) The electric field $E$ in a depletion layer is given by the relation $E = \frac{V}{d}$,where $V$ is the potential barrier and $d$ is the thickness of the depletion layer.Given: $V = 0.5 \ V$ and $d = 5.0 	imes 10^{-7} \ m$.Substituting the values:$E = \frac{0.5}{5.0 	imes 10^{-7}}$$E = \frac{0.5}{5.0} 	imes 10^7$$E = 0.1 	imes 10^7 \ V/m$$E = 1.0 	imes 10^6 \ V/m$.Therefore,the electric field is $1.0 	imes 10^6 \ V/m$.

The potential barrier of a $P-N$ junction is $0.5 \ V$. The thickness of the depletion layer is $5.0 \times 10^{-7} \ m$. Calculate the electric field.

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