If the wavelength of light in air is 4200, ma | vedclass

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(C) The refractive index $\mu$ is inversely proportional to the wavelength $\lambda$ of light in a medium,given by the relation $\mu = \frac{\lambda_{

Vedclass · Accepted Answer

$3150$

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(C) The refractive index $\mu$ is inversely proportional to the wavelength $\lambda$ of light in a medium,given by the relation $\mu = \frac{\lambda_{air}}{\lambda_{medium}}$.Given: $\lambda_{air} = 4200\, \mathring A$ and $\mu = 4/3$.Substituting the values into the formula: $\frac{4}{3} = \frac{4200}{\lambda_{water}}$.Rearranging for $\lambda_{water}$: $\lambda_{water} = \frac{4200 	imes 3}{4}$.$\lambda_{water} = 1050 	imes 3 = 3150\, \mathring A$.

If the wavelength of light in air is $4200\, \mathring A$,what will be the wavelength of light in water $(\mu = 4/3)$ in $\mathring A$?

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