The angle of deviation for a ray passing thro | vedclass

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Question

(A) The angle of deviation for a thin prism is given by the formula $\delta = (\mu - 1)A$,where $\mu$ is the refractive index of the material and $A$

Vedclass · Accepted Answer

$15$

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(A) The angle of deviation for a thin prism is given by the formula $\delta = (\mu - 1)A$,where $\mu$ is the refractive index of the material and $A$ is the refracting angle of the prism.From the figure,the total refracting angle of the prism is $A = 30^o + 30^o = 60^o$.Given that the initial deviation is $\delta = 30^o$,we have $30^o = (\mu - 1)60^o$,which implies $(\mu - 1) = 0.5$.If one half of the prism is removed,the new refracting angle becomes $A' = 30^o$.The new angle of deviation will be $\delta' = (\mu - 1)A' = 0.5 	imes 30^o = 15^o$.

The angle of deviation for a ray passing through the given prism is $30^o$. If one half of the prism is removed,what will be the new angle of deviation in degrees?

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