The magnification of a compound microscope is $30$. If the focal length of the eyepiece is $5 \, cm$,what is the magnification of the objective lens?

The total magnification produced by a compound microscope is $24$ when the final image is formed at the least distance of distinct vision. If the focal length of the eyepiece is $5 \ cm$, the magnification produced by the objective is

The near vision of an average person is $25 \, cm$. To view an object with an angular magnification of $10$,what should be the power of the microscope?

The magnification of a compound microscope is $30$. The focal length of the eyepiece is $5 \ cm$ and the image is formed at the near point (distance of distinct vision) of $25 \ cm$. The magnification of the objective lens is:

The intermediate image formed by an objective lens of a compound microscope is

Which of the following statements are true in the context of a Compound Microscope?
$(A)$ The objective lens forms a virtual and magnified image.
$(B)$ The objective lens has a very short focal length.
$(C)$ The eyepiece acts as a simple magnifying glass.
$(D)$ The eyepiece is a concave lens.