The intensities of two coherent sources are 9 | vedclass

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(D) The phase difference $\phi$ is related to the path difference $\Delta x$ by the formula $\phi = \frac{2\pi}{\lambda} \Delta x$.Given the path diff

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$25I$

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(D) The phase difference $\phi$ is related to the path difference $\Delta x$ by the formula $\phi = \frac{2\pi}{\lambda} \Delta x$.Given the path difference $\Delta x = 11\lambda$,the phase difference is $\phi = \frac{2\pi}{\lambda} 	imes 11\lambda = 22\pi$.Since the phase difference is an even multiple of $\pi$,the interference is constructive.The resultant intensity $I_R$ is given by $I_R = (\sqrt{I_1} + \sqrt{I_2})^2$.Substituting the given values $I_1 = 9I$ and $I_2 = 4I$:$I_R = (\sqrt{9I} + \sqrt{4I})^2 = (3\sqrt{I} + 2\sqrt{I})^2 = (5\sqrt{I})^2 = 25I$.

The intensities of two coherent sources are $9I$ and $4I$. The intensity at a point where the path difference is $11\lambda$ is:

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