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(B) The Doppler shift in wavelength is given by the formula $\Delta \lambda = \lambda \frac{v}{c}$,where $\Delta \lambda$ is the change in wavelength,

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$3 	imes 10^6 \, m/s$

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(B) The Doppler shift in wavelength is given by the formula $\Delta \lambda = \lambda \frac{v}{c}$,where $\Delta \lambda$ is the change in wavelength,$\lambda$ is the original wavelength,$v$ is the velocity of the source,and $c$ is the speed of light.Given: $\lambda = 3700 \, \mathring{A}$,observed wavelength $\lambda' = 3737 \, \mathring{A}$,and $c = 3 	imes 10^8 \, m/s$.The change in wavelength is $\Delta \lambda = \lambda' - \lambda = 3737 \, \mathring{A} - 3700 \, \mathring{A} = 37 \, \mathring{A}$.Substituting the values into the formula: $37 = 3700 	imes \frac{v}{3 	imes 10^8}$.Solving for $v$: $v = \frac{37 	imes 3 	imes 10^8}{3700} = \frac{111 	imes 10^8}{3700} = 0.03 	imes 10^8 = 3 	imes 10^6 \, m/s$.

The wavelength of light coming from a star is $3700 \, \mathring{A}$. If the observed wavelength from Earth is $3737 \, \mathring{A}$,what is the velocity of the star? [$c = 3 \times 10^8 \, m/s$]

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