Identify the correct order of boiling points | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The boiling point depends on the strength of intermolecular forces,primarily hydrogen bonding and dipole-dipole interactions.$III$ $(CH_3CH_2CH_2C

Vedclass · Accepted Answer

$III > I > II$

Vedclass · Answer

(B) The boiling point depends on the strength of intermolecular forces,primarily hydrogen bonding and dipole-dipole interactions.$III$ $(CH_3CH_2CH_2COOH)$ is a carboxylic acid,which forms strong intermolecular hydrogen bonds (dimers),leading to the highest boiling point.$I$ $(CH_3CH_2CH_2CH_2OH)$ is an alcohol,which also forms intermolecular hydrogen bonds,but they are generally weaker than those in carboxylic acids.$II$ $(CH_3CH_2CH_2CHO)$ is an aldehyde,which exhibits only dipole-dipole interactions and lacks hydrogen bonding,resulting in the lowest boiling point.Therefore,the correct order is $III > I > II$.

Identify the correct order of boiling points for the following compounds:
$I. \, CH_3CH_2CH_2CH_2OH$
$II. \, CH_3CH_2CH_2CHO$
$III. \, CH_3CH_2CH_2COOH$

Similar Questions

$CH_2=CH-CO-OCH_3$ (methyl acrylate,bp $81^\circ C$) + $CH_3-CH_2-CH_2-CH_2-OH$ (n-butyl alcohol,bp $117^\circ C$) $\xrightarrow{TsOH, \Delta} (A)$ (bp $145^\circ C$) + $CH_3OH$ (bp $65^\circ C$). Product $(A)$ of the above reaction is:

Acetyl chloride is reduced with $LiAlH_4$. The product formed is:

Identify the major product formed in the following reaction sequence:

The correct decreasing order for acidic strength is

Formic acid and Acetic acid can be differentiated by

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the correct order of boiling points for the following compounds:$I. \, CH_3CH_2CH_2CH_2OH$$II. \, CH_3CH_2CH_2CHO$$III. \, CH_3CH_2CH_2COOH$