An organic compound with the molecular formul | vedclass

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(C) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether. Since the compound does not react with sodium metal,it must be an

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$1-$Methoxypropane

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(C) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether. Since the compound does not react with sodium metal,it must be an ether. $1-$Methoxypropane $(CH_3-O-CH_2CH_2CH_3)$ reacts with excess $HI$ as follows: $CH_3-O-CH_2CH_2CH_3 + 2HI \rightarrow CH_3I + CH_3CH_2CH_2I + H_2O$. This reaction produces two distinct alkyl halides: methyl iodide and propyl iodide.

An organic compound with the molecular formula $C_4H_{10}O$ does not react with sodium metal. Upon reaction with excess $HI$,it yields only two types of halides. Identify the compound.

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