CH_3-CO-CH_3 + [O] xrightarrow{SeO_2} P + Se | vedclass

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Question

(A) $SeO_2$ is an oxidizing agent that specifically oxidizes the $\alpha$-methylene or $\alpha$-methyl group of a carbonyl compound to a carbonyl grou

Vedclass · Accepted Answer

$CH_3-CO-CHO$

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(A) $SeO_2$ is an oxidizing agent that specifically oxidizes the $\alpha$-methylene or $\alpha$-methyl group of a carbonyl compound to a carbonyl group,forming a $1,2-$dicarbonyl compound. In the reaction of acetone $(CH_3-CO-CH_3)$ with $SeO_2$,one of the $\alpha$-methyl groups is oxidized to an aldehyde group. The reaction is: $CH_3-CO-CH_3 + SeO_2 \rightarrow CH_3-CO-CHO + Se + H_2O$. Thus,$P$ is $CH_3-CO-CHO$ (methylglyoxal or pyruvaldehyde).

$CH_3-CO-CH_3 + [O] \xrightarrow{SeO_2} P + Se + H_2O$. What is $P$ here?

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