What product is obtained when two moles of acetic acid are heated with $P_2O_5$?

  • A
    $2$ moles of ethyl alcohol
  • B
    Formic anhydride
  • C
    Acetic anhydride
  • D
    $2$ moles of methyl cyanide

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An optically active compound $'X'$ having molecular formula $C_4H_8O_3$ evolves $CO_2$ with $NaHCO_3$. $'X'$ on treatment with $LiAlH_4$ gives an achiral compound. Then $'X'$ is

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Ammonium acetate reacts with acetic acid at $110\,^{\circ}C$ to form:

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

Identify product $A$ in the following reaction.
$2 CH_3COOH \xrightarrow{\Delta, P_2O_5} A + H_2O$

When ethane-$1, 2$-dioic acid is heated with conc. $H_2SO_4$,it gives

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