In the $HCOO^{-}$ anion,the two carbon-oxygen bonds are found to be of equal length. What is the reason for this?

  • A
    The anion $HCOO^{-}$ has two equivalent resonance structures.
  • B
    The anion is formed after the removal of a proton from the acid molecule.
  • C
    The electronic orbitals of the carbon atom are in hybridization.
  • D
    The $C=O$ bond is weaker than the $C-O$ bond.

Explore More

Similar Questions

The correct order of sulphur-oxygen bond order in $SO_3$,$S_2O_3^{2-}$,and $SO_4^{2-}$ is:

What is the number of Lewis structures for $NO_2^{-}$?

Compare the relative stability of the following resonating structures:
$(i)$ $CH_3-CH=C(CN)-COCH_3$
(ii) $CH_3-CH=C(CN)-C^+(O^-)CH_3$
(iii) $CH_3-C^+(H)-C(CN)=C(O^-)CH_3$
(Note: The structures are provided in the image.)

Difficult
View Solution

Which one of the following is not a resonance structure of $CO_2$?

What is a resonance structure? Why are resonance structures required? Explain with a suitable example.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo