When propionic acid is reacted with aqueous sodium carbonate,$CO_2$ is released. From where does the $'C'$ of $CO_2$ come?

  • A
    From the methyl group
  • B
    From the carboxylic group
  • C
    From the methylene group
  • D
    From the carbonate

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Similar Questions

Propionic acid is subjected to reduction with hydroiodic acid in the presence of a little $P$,the product formed is

Select the acid with the highest $K_a$ (i.e.,lowest $pK_a$).

The $OH$ group of an alcohol or the $-COOH$ group of a carboxylic acid can be replaced by $-Cl$ using:

$Ph-CO_2H$ $\xrightarrow{SOCl_2} A$ $\xrightarrow{Me_2NH} B$ $\xrightarrow{(C)} Ph-CHO$. The unknown reagent $(C)$ is:

$HOOC-(CH_2)_n-COOH \xrightarrow[\Delta]{} \text{product}$
At what value of $(n)$ will the given compound not evolve $CO_2$ gas?

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