Which of the following compounds will NOT pro | vedclass

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(D) Acetamide $(CH_3CONH_2)$ is formed when compounds containing an acetyl group $(CH_3CO-)$ react with ammonia $(NH_3)$.$1$. Acetic acid $(CH_3COOH)$

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Methyl propionate

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(D) Acetamide $(CH_3CONH_2)$ is formed when compounds containing an acetyl group $(CH_3CO-)$ react with ammonia $(NH_3)$.$1$. Acetic acid $(CH_3COOH)$ reacts with $NH_3$ to form ammonium acetate,which on heating gives acetamide.$2$. Acetyl chloride $(CH_3COCl)$ reacts with $NH_3$ to form acetamide.$3$. Methyl acetate $(CH_3COOCH_3)$ reacts with $NH_3$ to form acetamide.$4$. Methyl propionate $(CH_3CH_2COOCH_3)$ contains a propionyl group $(CH_3CH_2CO-)$ instead of an acetyl group. Therefore,it reacts with $NH_3$ to produce propionamide $(CH_3CH_2CONH_2)$ and methanol $(CH_3OH)$: $CH_3CH_2COOCH_3 + NH_3 	o CH_3CH_2CONH_2 + CH_3OH$.

Which of the following compounds will $NOT$ produce acetamide upon reaction with ammonia?

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