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(A) The reaction involves the alkaline hydrolysis (saponification) of an ester. When an ester is boiled with alcoholic $KOH$,it forms the potassium sa

Vedclass · Accepted Answer

Ethyl benzoate

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(A) The reaction involves the alkaline hydrolysis (saponification) of an ester. When an ester is boiled with alcoholic $KOH$,it forms the potassium salt of the corresponding carboxylic acid and an alcohol. Upon acidification with $HCl$,the potassium salt is converted into the free carboxylic acid. If the resulting carboxylic acid is a solid at room temperature and insoluble in water,it will precipitate as a white solid. Among the given options,$Ethyl \ benzoate$ $(C_6H_5COOC_2H_5)$ undergoes hydrolysis to form potassium benzoate $(C_6H_5COOK)$ and ethanol. Potassium benzoate,upon acidification with $HCl$,yields benzoic acid $(C_6H_5COOH)$,which is a white crystalline solid that is sparingly soluble in water and thus precipitates out. The reaction is: $C_6H_5COOC_2H_5 + KOH \rightarrow C_6H_5COOK + C_2H_5OH$ $C_6H_5COOK + HCl \rightarrow C_6H_5COOH(s) + KCl$

An organic compound is boiled with alcoholic potash. The product is cooled and acidified with $HCl$,resulting in the precipitation of a white solid. What could be the starting compound?

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