$_{92}U^{235}$ belongs to group $III-B$ of the periodic table. If it loses one $\alpha$-particle,the new element will belong to group:

When a radium atom,which is placed in group $II$,loses an $\alpha$-particle,a new element is formed which should be placed in group ........

In the reaction $Po$ $\xrightarrow{-\alpha} Pb$ $\xrightarrow{-\beta} Bi$,if $Bi$ belongs to group $15$,to which group does $Po$ belong?

$_{84}Po^{210} \xrightarrow{} _{82}Pb^{206} + _{2}He^{4}$. From the above equation,deduce the position of polonium in the periodic table (lead belongs to group $IV A$).

Emission of a $\beta$-particle by an atom of an element results in the formation of its

Group displacement law states that the emission of $\alpha$ or $\beta$ particles results in the daughter element occupying a position,in the periodic table,either to the left or right of that of the parent element. Which one of the following alternatives gives the correct position of the daughter element?

On emission of $\alpha$ particles

On emission of $\beta$ particles