The relation R is defined as R = {(4, 5), (1, | vedclass

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(A) Given $R = \{(4, 5), (1, 4), (4, 6), (7, 6), (3, 7)\}$.Then $R^{-1} = \{(5, 4), (4, 1), (6, 4), (6, 7), (7, 3)\}$.To find $R^{-1} o R$,we look for

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$\{(1, 1), (4, 4), (4, 7), (7, 4), (7, 7), (3, 3)\}$

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(A) Given $R = \{(4, 5), (1, 4), (4, 6), (7, 6), (3, 7)\}$.Then $R^{-1} = \{(5, 4), (4, 1), (6, 4), (6, 7), (7, 3)\}$.To find $R^{-1} o R$,we look for pairs $(x, z)$ such that there exists $y$ where $(x, y) \in R$ and $(y, z) \in R^{-1}$.$1$. For $(4, 5) \in R$ and $(5, 4) \in R^{-1}$,we get $(4, 4) \in R^{-1} o R$.$2$. For $(1, 4) \in R$ and $(4, 1) \in R^{-1}$,we get $(1, 1) \in R^{-1} o R$.$3$. For $(4, 6) \in R$ and $(6, 4) \in R^{-1}$,we get $(4, 4) \in R^{-1} o R$.$4$. For $(4, 6) \in R$ and $(6, 7) \in R^{-1}$,we get $(4, 7) \in R^{-1} o R$.$5$. For $(7, 6) \in R$ and $(6, 4) \in R^{-1}$,we get $(7, 4) \in R^{-1} o R$.$6$. For $(7, 6) \in R$ and $(6, 7) \in R^{-1}$,we get $(7, 7) \in R^{-1} o R$.$7$. For $(3, 7) \in R$ and $(7, 3) \in R^{-1}$,we get $(3, 3) \in R^{-1} o R$.Combining these,$R^{-1} o R = \{(1, 1), (4, 4), (4, 7), (7, 4), (7, 7), (3, 3)\}$.

The relation $R$ is defined as $R = \{(4, 5), (1, 4), (4, 6), (7, 6), (3, 7)\}$. Then $R^{-1} o R$ is:

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