Let A = {1, 2, 3, 4} and R = {(2, 2), (3, 3), | vedclass

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(C) relation $R$ on a set $A$ is reflexive if $(a, a) \in R$ for all $a \in A$. Here,$A = \{1, 2, 3, 4\}$. For $R$ to be reflexive,$(1, 1), (2, 2), (3

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Transitive

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(C) relation $R$ on a set $A$ is reflexive if $(a, a) \in R$ for all $a \in A$. Here,$A = \{1, 2, 3, 4\}$. For $R$ to be reflexive,$(1, 1), (2, 2), (3, 3), (4, 4)$ must be in $R$. Since $(1, 1) 
otin R$,$R$ is not reflexive.$A$ relation $R$ is symmetric if $(a, b) \in R \implies (b, a) \in R$. Here,$(1, 2) \in R$,but $(2, 1) 
otin R$. Therefore,$R$ is not symmetric.$A$ relation $R$ is transitive if $(a, b) \in R$ and $(b, c) \in R \implies (a, c) \in R$. Here,$(1, 2) \in R$ and $(2, 2) \in R$. This implies $(1, 2)$ must be in $R$,which is true. Checking other pairs,we find that for all $(a, b), (b, c) \in R$,$(a, c) \in R$ holds. Thus,$R$ is transitive.Therefore,the correct option is $C$.

Let $A = \{1, 2, 3, 4\}$ and $R = \{(2, 2), (3, 3), (4, 4), (1, 2)\}$ be a relation on $A$. Then $R$ is:

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