How can a solid sphere and a hollow sphere of | vedclass

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(B) When rolling down an inclined plane,the acceleration of a body is given by $a = \frac{g \sin 	heta}{1 + \frac{I}{MR^2}}$.For a solid sphere,the m

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By rolling them simultaneously down an inclined plane.

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(B) When rolling down an inclined plane,the acceleration of a body is given by $a = \frac{g \sin 	heta}{1 + \frac{I}{MR^2}}$.For a solid sphere,the moment of inertia $I = \frac{2}{5}MR^2$,so $a_{solid} = \frac{g \sin 	heta}{1 + 0.4} = \frac{g \sin 	heta}{1.4} \approx 0.71g \sin 	heta$.For a hollow sphere,the moment of inertia $I = \frac{2}{3}MR^2$,so $a_{hollow} = \frac{g \sin 	heta}{1 + 0.67} = \frac{g \sin 	heta}{1.67} \approx 0.60g \sin 	heta$.Since the acceleration of the solid sphere is greater,it will reach the bottom of the inclined plane faster than the hollow sphere.

How can a solid sphere and a hollow sphere of the same material and same size be distinguished without weighing them?

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