CH_3 - CHCl - CH_2 - CH_3 has a chiral center | vedclass

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(B) To determine the $R$-configuration,we assign priorities to the groups attached to the chiral carbon based on the Cahn-Ingold-Prelog $(CIP)$ rules:

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$C_2H_5 - C(Cl)(CH_3) - H$

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(B) To determine the $R$-configuration,we assign priorities to the groups attached to the chiral carbon based on the Cahn-Ingold-Prelog $(CIP)$ rules: $Cl(1) > C_2H_5(2) > CH_3(3) > H(4)$.In the Fischer projection,the configuration is $R$ if the sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise,provided the lowest priority group $(H)$ is on a vertical bond.Analyzing the structures,the configuration $R$ corresponds to the arrangement where the priority sequence is clockwise. Based on the provided image,the third structure shows the $R$-configuration where $Cl$ is on the left,$C_2H_5$ is on top,$CH_3$ is on the right,and $H$ is at the bottom. This corresponds to the structure $C_2H_5 - C(Cl)(CH_3) - H$ (Option $B$).

$CH_3 - CHCl - CH_2 - CH_3$ has a chiral center. Which one of the following represents its $R$-configuration?

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