1,g of water at 100,^{circ}C and 10^5,Pa pres | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given: Mass $m = 1\,g = 10^{-3}\,kg$,Pressure $P = 10^5\,Pa$,Volume of steam $V_s = 1841\,cm^3 = 1841 	imes 10^{-6}\,m^3$,Latent heat $L = 2250\,

Vedclass · Accepted Answer

$2066$

Vedclass · Answer

(C) Given: Mass $m = 1\,g = 10^{-3}\,kg$,Pressure $P = 10^5\,Pa$,Volume of steam $V_s = 1841\,cm^3 = 1841 	imes 10^{-6}\,m^3$,Latent heat $L = 2250\,J/g = 2250 	imes 10^3\,J/kg$.The volume of $1\,g$ of water is $V_w = \frac{m}{ho} = \frac{1\,g}{1\,g/cm^3} = 1\,cm^3 = 10^{-6}\,m^3$.According to the first law of thermodynamics,$\Delta Q = \Delta U + W$,where $W = P(V_s - V_w)$.Heat absorbed $\Delta Q = m 	imes L = 1\,g 	imes 2250\,J/g = 2250\,J$.Work done $W = P(V_s - V_w) = 10^5\,Pa 	imes (1841 	imes 10^{-6} - 1 	imes 10^{-6})\,m^3 = 10^5 	imes 1840 	imes 10^{-6} = 184\,J$.Change in internal energy $\Delta U = \Delta Q - W = 2250\,J - 184\,J = 2066\,J$.

$1\,g$ of water at $100\,^{\circ}C$ and $10^5\,Pa$ pressure converts into $1841\,cm^3$ of steam at constant temperature and pressure. If the latent heat of vaporization of water is $2250\,J/g$,the change in internal energy of water in this process is ..... $J$.

Similar Questions

$A$ system is given $300$ calories of heat and it does $600$ joules of work. How much does the internal energy of the system change in this process? $(1 \text{ calorie} = 4.18 \text{ joules})$

$A$ total of $48 \,J$ heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by $2^{\circ} C$. The work done by the gas is : (Given,$R=8.3 \,J \,K^{-1} \,mol^{-1}$.) (in $\,J$)

In a thermodynamic process,the pressure of a fixed mass of a gas is changed in such a manner that the gas releases $30 \ J$ of heat and $10 \ J$ of work is done on the gas. If the initial internal energy of the gas was $30 \ J$,then the final internal energy will be ........ $J$.

$A$ system performs work $\Delta W$ when an amount of heat $\Delta Q$ is added to the system. The corresponding change in the internal energy is $\Delta U$. Which of the following is a unique function of the initial and final states (irrespective of the mode of change)?

Heat given to a system is $35 \ J$ and work done by the system is $15 \ J$. The change in the internal energy of the system will be ..... $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module