A block of mass m slides down a plane incline | vedclass

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Question

(A) The energy lost due to friction $(E)$ as a block slides down an inclined plane of length $d$ is given by the work done against the frictional forc

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Increasing the angle of inclination

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(A) The energy lost due to friction $(E)$ as a block slides down an inclined plane of length $d$ is given by the work done against the frictional force.The frictional force is $f = \mu_k N$, where $N = mg \cos 	heta$ is the normal force.Thus, the energy lost is $E = f \cdot d = \mu_k (mg \cos 	heta) d$.Analyzing the variables:$1$. Increasing the angle of inclination $(	heta)$: As $	heta$ increases, $\cos 	heta$ decreases, so the energy lost decreases.$2$. Increasing the distance $(d)$: Energy lost increases linearly with $d$.$3$. Increasing the acceleration due to gravity $(g)$: Energy lost increases linearly with $g$.$4$. Increasing the mass $(m)$: Energy lost increases linearly with $m$.Therefore, increasing the angle of inclination does not increase the energy lost; it decreases it.

$A$ block of mass $m$ slides down a plane inclined at an angle $\theta$. Which of the following will $NOT$ increase the energy lost by the block due to friction?

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