$A$ solid uniform disk of mass $m$ rolls without slipping down a fixed inclined plane with an acceleration $a$. The frictional force on the disk due to the surface of the plane is:

$A$ spherical object of mass $M$ and radius $R$ has a moment of inertia $I$ about its axis. If this object rolls down an inclined plane of angle $\theta$ without slipping,its acceleration is given by:

$A$ solid cylinder of mass $M$ and radius $R$ rolls without slipping down an inclined plane making an angle $\theta$ with the horizontal. Then its acceleration is:

$A$ hollow cylinder is rolling on an inclined plane,inclined at an angle of $30^{\circ}$ to the horizontal. Its speed after travelling a distance of $10 \ m$ will be .......... $m/s$.

$A$ cylinder rolls up an inclined plane to a certain height and then rolls down. (During these motions,the cylinder rolls without slipping). What are the directions of the frictional force acting on the cylinder?

$A$ solid cylinder of diameter $30 \ cm$ is rolled down an inclined plane from a height of $2 \ m$. If there is no energy loss due to friction,the angular velocity at the base of the plane is ....... $rad/s$. (Take $g = 10 \ m/s^2$)