(Delta H - Delta U) for the formation of carb | vedclass

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(D) The chemical equation for the formation of $CO$ is: $C_{(s)} + \frac{1}{2} O_{2(g)} \rightarrow CO_{(g)}$ From the first law of thermodynamics,we

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$1238.78$

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(D) The chemical equation for the formation of $CO$ is: $C_{(s)} + \frac{1}{2} O_{2(g)} ightarrow CO_{(g)}$ From the first law of thermodynamics,we know that $\Delta H = \Delta U + \Delta n_g RT$. Rearranging the equation,we get $\Delta H - \Delta U = \Delta n_g RT$. Here,$\Delta n_g$ is the change in the number of moles of gaseous species: $\Delta n_g = n_{p(g)} - n_{r(g)} = 1 - \frac{1}{2} = \frac{1}{2}$. Substituting the values: $\Delta H - \Delta U = \frac{1}{2} 	imes 8.314 	imes 298 = 1238.78 \ J \ mol^{-1}$.

$(\Delta H - \Delta U)$ for the formation of carbon monoxide $(CO)$ from its elements at $298 \ K$ is ............. $J \ mol^{-1}$. $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$

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