CsCl crystallises in a body-centred cubic (BC | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $BCC$ unit cell of $CsCl$,the $Cs^{+}$ ion is at the body center and $Cl^{-}$ ions are at the corners.The body diagonal of the cube is equal

Vedclass · Accepted Answer

$r_{Cs^{+}} + r_{Cl^{-}} = \frac{\sqrt{3}}{2} a$

Vedclass · Answer

(C) In a $BCC$ unit cell of $CsCl$,the $Cs^{+}$ ion is at the body center and $Cl^{-}$ ions are at the corners.The body diagonal of the cube is equal to $\sqrt{3} a$.Along the body diagonal,the ions are in contact such that the distance is $r_{Cl^{-}} + 2r_{Cs^{+}} + r_{Cl^{-}} = \sqrt{3} a$.This simplifies to $2(r_{Cs^{+}} + r_{Cl^{-}}) = \sqrt{3} a$.Therefore,the correct expression is $r_{Cs^{+}} + r_{Cl^{-}} = \frac{\sqrt{3}}{2} a$.

$CsCl$ crystallises in a body-centred cubic $(BCC)$ lattice. If '$a$' is its edge length,then which of the following expressions is correct?

Similar Questions

All of the following share the same crystal structure except:

In a face-centered cubic arrangement of $A$ and $B$ atoms,$A$ atoms are at the corners of the unit cell and $B$ atoms are at the face centers. If one of the $B$ atoms is missing from one of the faces in the unit cell,the simplest formula of the compound is:

The coordination number of the point $B$ for a solid with the following structure is:

The number of spheres contained $(i)$ in one body centred cubic unit cell and $(ii)$ in one face centred cubic unit cell,is

In zinc blende structure,the coordination number of $Zn^{2+}$ ion is

Vedclass Test Series

Exam Paper Generator

Online Exam Module