HBr reacts with CH_2=CH-OCH_3 under anhydrous | vedclass

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Question

(B) The reaction involves electrophilic addition of $HBr$ to the vinyl ether.$H^{+}$ from $HBr$ adds to the terminal carbon $(CH_2)$ to form a resonan

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$CH_3-CHBr-OCH_3$

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(B) The reaction involves electrophilic addition of $HBr$ to the vinyl ether.$H^{+}$ from $HBr$ adds to the terminal carbon $(CH_2)$ to form a resonance-stabilized carbocation:$CH_2=CH-OCH_3 + H^{+} \rightarrow CH_3-C^{+}H-OCH_3 \leftrightarrow CH_3-CH=O^{+}-CH_3$The $Br^{-}$ ion then attacks the carbocation to form the product:$CH_3-C^{+}H-OCH_3 + Br^{-} \rightarrow CH_3-CHBr-OCH_3$

$HBr$ reacts with $CH_2=CH-OCH_3$ under anhydrous conditions at room temperature to give:

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