The average speed (u_{avg}) of O_2 gas at pi | vedclass

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(D) The formula for average speed is $u_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Using the ideal gas equation $PV = nRT$,we find $RT = \frac{PV}{n}$.Given $P

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$\sqrt{10^9} \ m/s$

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(D) The formula for average speed is $u_{avg} = \sqrt{\frac{8RT}{\pi M}}$.Using the ideal gas equation $PV = nRT$,we find $RT = \frac{PV}{n}$.Given $P = \pi 	imes 10 \ bar = \pi 	imes 10^6 \ Pa$,$V = 8 \ m^3$,$n = 2 \ mol$,and $M = 32 	imes 10^{-3} \ kg/mol$.$RT = \frac{(\pi 	imes 10^6) 	imes 8}{2} = 4\pi 	imes 10^6 \ J/mol$.Substituting into the formula: $u_{avg} = \sqrt{\frac{8 	imes (4\pi 	imes 10^6)}{\pi 	imes (32 	imes 10^{-3})}} = \sqrt{\frac{32\pi 	imes 10^6}{32\pi 	imes 10^{-3}}} = \sqrt{10^9} \ m/s$.

The average speed $(u_{avg})$ of $O_2$ gas at $\pi \times 10 \ bar$ pressure in an $8 \ m^3$ container containing $2 \ moles$ is:

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