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(C) The reaction is a cross-aldol condensation between $p$-methylbenzaldehyde and $p$-methylacetophenone in the presence of a base $(\bar{O}H)$ and he

Vedclass · Accepted Answer

$p-CH_3-C_6H_4-CH=CH-CO-C_6H_4-p-CH_3$

Vedclass · Answer

(C) The reaction is a cross-aldol condensation between $p$-methylbenzaldehyde and $p$-methylacetophenone in the presence of a base $(\bar{O}H)$ and heat $(\Delta)$.In this reaction,the ketone ($p$-methylacetophenone) acts as the enolate donor because it has $\alpha$-hydrogens,while the aldehyde ($p$-methylbenzaldehyde) acts as the electrophilic acceptor.The enolate formed from $p$-methylacetophenone attacks the carbonyl carbon of $p$-methylbenzaldehyde.Following the condensation and subsequent dehydration (due to heat),the final product is $p-CH_3-C_6H_4-CH=CH-CO-C_6H_4-p-CH_3$.

Predict the product of the following reaction:
$p-CH_3-C_6H_4-CHO + p-CH_3-C_6H_4-CO-CH_3 \xrightarrow{\bar{O}H, \Delta} \text{Product}$

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Predict the product of the following reaction:$p-CH_3-C_6H_4-CHO + p-CH_3-C_6H_4-CO-CH_3 \xrightarrow{\bar{O}H, \Delta} \text{Product}$