The P-V diagram of a diatomic gas is a straig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The $P-V$ diagram is a straight line passing through the origin,which implies $P \propto V$,or $P = kV$ where $k$ is a constant.This can be writte

Vedclass · Accepted Answer

$3\ R$

Vedclass · Answer

(C) The $P-V$ diagram is a straight line passing through the origin,which implies $P \propto V$,or $P = kV$ where $k$ is a constant.This can be written as $P V^{-1} = 	ext{constant}$.Comparing this with the polytropic process equation $P V^x = 	ext{constant}$,we get $x = -1$.The molar heat capacity $C$ for a polytropic process is given by $C = \frac{R}{\gamma - 1} + \frac{R}{1 - x}$.For a diatomic gas,the adiabatic index $\gamma = 1.4 = \frac{7}{5}$.Substituting the values: $C = \frac{R}{\frac{7}{5} - 1} + \frac{R}{1 - (-1)}$.$C = \frac{R}{\frac{2}{5}} + \frac{R}{2} = \frac{5R}{2} + \frac{R}{2}$.$C = \frac{6R}{2} = 3R$.

The $P-V$ diagram of a diatomic gas is a straight line passing through the origin. The molar heat capacity of the gas in the process will be:

Similar Questions

$A$ block of $200 \text{ g}$ mass moves with a uniform speed in a horizontal circular groove with vertical side walls of radius $20 \text{ cm}$. If the block takes $40 \text{ s}$ to complete one round,the normal force exerted by the side walls of the groove is:

The incentre of the triangle formed by the lines $x+y=1$,$x=1$,and $y=1$ is

The equation of the tangent to the curve $6y = 7 - x^3$ at the point $(1, 1)$ is:

$A$ solution of $Na_2SO_4$ in water is electrolysed using inert electrodes. The products at cathode and anode are respectively:

In which of the following is the hydration energy higher than the lattice energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module