Na and Li are placed in dry air. We get | vedclass

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(D) When exposed to dry air (which contains $O_2$ and $N_2$),$Li$ reacts with both $O_2$ and $N_2$ to form $Li_2O$ and $Li_3N$ respectively.$Na$ react

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$Na_2O$,$Li_3N$,$Li_2O$

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(D) When exposed to dry air (which contains $O_2$ and $N_2$),$Li$ reacts with both $O_2$ and $N_2$ to form $Li_2O$ and $Li_3N$ respectively.$Na$ reacts with $O_2$ to form $Na_2O$ (and $Na_2O_2$ depending on conditions),but it does not react with $N_2$ at room temperature.Therefore,the products obtained are $Na_2O$,$Li_2O$,and $Li_3N$.

$Na$ and $Li$ are placed in dry air. We get

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