[Cu(CN)_4]^{2-} is more stable than [Cu(NH_3) | vedclass

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(C) The stability of a coordination complex is determined by its stability constant $(K)$.$A$ higher value of the stability constant indicates a more

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both $(A)$ $\&$ $(B)$

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(C) The stability of a coordination complex is determined by its stability constant $(K)$.$A$ higher value of the stability constant indicates a more stable complex.$CN^{-}$ is a strong field ligand (a $\pi$-acceptor ligand) compared to $NH_3$,which leads to a stronger metal-ligand bond and a higher stability constant for the $[Cu(CN)_4]^{2-}$ complex.Therefore,both the higher stability constant and the stronger ligand nature of $CN^{-}$ contribute to the greater stability of $[Cu(CN)_4]^{2-}$.

$[Cu(CN)_4]^{2-}$ is more stable than $[Cu(NH_3)_4]^{2+}$ because :-

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