C_6H_5OH xrightarrow[Br_2]{OH^{ominus}} ; In | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of phenol with $Br_2$ in the presence of $OH^{\ominus}$ is an electrophilic aromatic substitution reaction.First,phenol reacts with $

Vedclass · Accepted Answer

All of these

Vedclass · Answer

(D) The reaction of phenol with $Br_2$ in the presence of $OH^{\ominus}$ is an electrophilic aromatic substitution reaction.First,phenol reacts with $OH^{\ominus}$ to form the phenoxide ion,which is highly activated towards electrophilic substitution.The phenoxide ion then reacts with $Br_2$ to form ortho-bromophenoxide ($2$-bromophenoxide) and para-bromophenoxide ($4$-bromophenoxide) intermediates.Further reaction with $Br_2$ leads to the formation of $2,4,6-$tribromophenol.Since all the given species ($2$-bromophenoxide,$4$-bromophenoxide,and $2,4-$dibromophenoxide) are formed as intermediates during the stepwise bromination process,the correct answer is 'All of these'.

$C_6H_5OH \xrightarrow[Br_2]{OH^{\ominus}} ; $ Intermediate of the given reaction is/are

Similar Questions

Which one of the following compounds is most acidic?

The rate of electrophilic substitution reaction in phenol is -

What product is formed when phenol reacts with $Br_2$ in $CCl_4$ at low temperature?

Assertion : Phenol is a stronger acid than ethanol.
Reason : Groups with $+M$ effect decrease acidity at $p-$position.

Vedclass Test Series

Exam Paper Generator

Online Exam Module