$Be_2C + H_2O \rightarrow Be(OH)_2 + X$
$CaC_2 + H_2O \rightarrow Ca(OH)_2 + Y$
Then $X$ and $Y$ are respectively:
$CaC_2 + H_2O \rightarrow Ca(OH)_2 + Y$
Then $X$ and $Y$ are respectively:
- A$CH_4, CH_4$
- B$CH_4, C_2H_6$
- C$CH_4, C_2H_2$
- D$C_2H_2, CH_4$
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