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(A) The reaction of alcohols with $HBr$ proceeds via an $S_N1$ mechanism,where the rate-determining step is the formation of a carbocation.The reactiv

Vedclass · Accepted Answer

$2-$Methylbutan$-2-$ol

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(A) The reaction of alcohols with $HBr$ proceeds via an $S_N1$ mechanism,where the rate-determining step is the formation of a carbocation.The reactivity order of alcohols towards $HBr$ is $3^{\circ} > 2^{\circ} > 1^{\circ}$ due to the stability of the resulting carbocation.$A$: $2-$Methylbutan$-2-$ol is a $3^{\circ}$ alcohol.$B$: $3-$Methylbutan$-2-$ol is a $2^{\circ}$ alcohol.$C$: Butan$-1-$ol is a $1^{\circ}$ alcohol.$D$: $2-$Methylbutan$-1-$ol is a $1^{\circ}$ alcohol.Since $3^{\circ}$ alcohols form the most stable carbocation,$2-$Methylbutan$-2-$ol reacts the fastest.

$HBr$ reacts fastest with

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