Cu^{2+} shows a coordination number of | vedclass

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(D) The coordination number of a metal ion in a complex depends on the nature of the ligands and the geometry of the complex.For the $Cu^{2+}$ ion,it

Vedclass · Accepted Answer

$4$ or $6$

Vedclass · Answer

(D) The coordination number of a metal ion in a complex depends on the nature of the ligands and the geometry of the complex.For the $Cu^{2+}$ ion,it commonly forms complexes with a coordination number of $4$ (e.g.,$[Cu(NH_3)_4]^{2+}$ with square planar geometry) and sometimes $6$ (e.g.,$[Cu(H_2O)_6]^{2+}$ with distorted octahedral geometry).Therefore,$Cu^{2+}$ can exhibit a coordination number of $4$ or $6$ depending on the ligands attached.

$A$. $[CoF_6]^{3-}$	$M$. $sp^3d^2$,paramagnetic
$B$. $[Mn(CN)_6]^{3-}$	$N$. $sp^3d^2$,diamagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$	$O$. $d^2sp^3$,paramagnetic
$D$. $[Zn(H_2O)_6]^{2+}$	$P$. $d^2sp^3$,diamagnetic

$Cu^{2+}$ shows a coordination number of

Similar Questions

Pick out the correct statement with respect to $[Mn(CN)_6]^{3-}.$

What is the type of hybridisation and the geometry respectively found in $[CoF_{6}]^{3-}$?

Match the correct option.
$A$. $[CoF_6]^{3-}$ $M$. $sp^3d^2$,paramagnetic
$B$. $[Mn(CN)_6]^{3-}$ $N$. $sp^3d^2$,diamagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$ $O$. $d^2sp^3$,paramagnetic
$D$. $[Zn(H_2O)_6]^{2+}$ $P$. $d^2sp^3$,diamagnetic

The species which has four unpaired electrons is

The shape of $MnO_4^-$ ion and the hybridisation of $Mn$ in $MnO_4^-$ is

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