KO_2 + H_2O to KOH + O_2 + product (X). Choos | vedclass

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(D) The reaction of potassium superoxide $(KO_2)$ with water is given by: $2KO_2 + 2H_2O 	o 2KOH + H_2O_2 + O_2$. Thus,the product $(X)$ is hydrogen

Vedclass · Accepted Answer

All of these

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(D) The reaction of potassium superoxide $(KO_2)$ with water is given by: $2KO_2 + 2H_2O 	o 2KOH + H_2O_2 + O_2$. Thus,the product $(X)$ is hydrogen peroxide $(H_2O_2)$. $H_2O_2$ has an open book-like structure in the gas phase. $H_2O_2$ is stabilized by the addition of urea to prevent its decomposition. $H_2O_2$ is sensitive to light and decomposes into water and oxygen in the presence of light,hence it is stored in wax-lined colored bottles. Therefore,all the given statements are correct.

$KO_2 + H_2O \to KOH + O_2 +$ product $(X)$. Choose the correct statement about product $(X)$.

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