$R-NH_2 \to R-NH-CH_3$ (major product). The correct sequence of reagents is:
- A$CH_3-CO-Cl$
- B$CH_3I$ (excess)
- C$CHCl_3 + KOH$ followed by $LiAlH_4$
- D$NaNO_2 + HCl$ $(0-5^\circ C)$; $(CH_3)_2NH$
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Similar Questions
Aniline does not undergo
MediumKCET 2023
View SolutionIdentify $X$ and $Y$ in the following reactions:
$Nitrobenzene \xrightarrow{Zn/NH_4Cl} X$
$Nitrobenzene \xrightarrow{Zn + KOH/C_2H_5OH} Y$
$Nitrobenzene \xrightarrow{Zn/NH_4Cl} X$
$Nitrobenzene \xrightarrow{Zn + KOH/C_2H_5OH} Y$
Benzene diazonium chloride on reaction with aniline in a mild alkaline medium forms:
Consider the following compounds:
$I. CH_3-CH_2-NH_2$
$II. Ph-CH_2-NH_2$
$III. Ph-NH_2$
The correct order of their basic strength is:
$I. CH_3-CH_2-NH_2$
$II. Ph-CH_2-NH_2$
$III. Ph-NH_2$
The correct order of their basic strength is:
Difficult
View SolutionWhat is the correct sequence of reagents used for converting nitrobenzene into $m$-dibromobenzene?
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