A 1 , M solution of glucose reaches dissociat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given reaction is $C_6H_{12}O_6 ightleftharpoons 6HCHO$. The formation reaction is $6HCHO ightleftharpoons C_6H_{12}O_6$ with $K_1 = 6 	i

Vedclass · Accepted Answer

$1.6 	imes 10^{-4} \, M$

Vedclass · Answer

(D) The given reaction is $C_6H_{12}O_6 ightleftharpoons 6HCHO$. The formation reaction is $6HCHO ightleftharpoons C_6H_{12}O_6$ with $K_1 = 6 	imes 10^{22}$. The dissociation reaction is the reverse,so $K_2 = \frac{1}{K_1} = \frac{1}{6 	imes 10^{22}}$. For the reaction $C_6H_{12}O_6 ightleftharpoons 6HCHO$,the equilibrium constant $K = (K_2)^{1/6} = (\frac{1}{6 	imes 10^{22}})^{1/6} \approx 1.6 	imes 10^{-4}$. Since the initial concentration of glucose is $1 \, M$,at equilibrium $[C_6H_{12}O_6] \approx 1 \, M$. Thus,$[HCHO]^6 = K 	imes [C_6H_{12}O_6] = 1.6 	imes 10^{-4} 	imes 1$. $[HCHO] = (1.6 	imes 10^{-4})^{1/6} \approx 0.26 \, M$. Note: Given the options,the question implies calculating the equilibrium constant for the dissociation step directly as $K = (6 	imes 10^{22})^{-1/6} \approx 1.6 	imes 10^{-4}$.

$A$ $1 \, M$ solution of glucose reaches dissociation equilibrium according to the equation $C_6H_{12}O_6 \rightleftharpoons 6HCHO$. What is the concentration of $HCHO$ at equilibrium if the equilibrium constant $K_c$ for the formation of glucose from formaldehyde is $6 \times 10^{22}$?

Similar Questions

In the reaction $A + 2B \rightleftharpoons 2C$,if $2$ moles of $A$,$3.0$ moles of $B$ and $2.0$ moles of $C$ are placed in a $2.0 \ L$ flask and the equilibrium concentration of $C$ is $0.5 \ mol/L$. The equilibrium constant $K_c$ for the reaction is:

For the reaction $A_{(g)} + 2B_{(g)} \rightleftharpoons 2C_{(g)}$,if the reaction is carried out in a constant volume vessel starting with equal amounts of $A$ and $B$,which of the following will be true at equilibrium?

For the reaction $H_{2(g)} + I_{2(g)} \rightleftharpoons 2HI_{(g)}$,the value of $K_c$ at $440 \ ^oC$ is $50$. If the reaction is initiated in a $1 \ L$ flask with $1 \ mol$ of $H_2$,$2 \ mol$ of $I_2$,and $3 \ mol$ of $HI$,then the equilibrium concentration of $HI$ will be .......... $M$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module