$A$ $2\,V$ battery forward biases a diode. There is a drop of $0.5\,V$ across the diode which is independent of current. Also,a current greater than $10\,mA$ produces large joule heat and damages the diode. If the diode is to be operated at $5\,mA$,the series resistance to be used is:

  • A
    $3\,k\Omega$
  • B
    $300\,k\Omega$
  • C
    $300\,\Omega$
  • D
    $200\,k\Omega$

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