A 2.0 text{ cm} tall object is placed perpend | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Object height $O = 2.0 	ext{ cm}$,Focal length $f = +10 	ext{ cm}$,Object distance $u = -15 	ext{ cm}$.Using the lens formula $\frac{1}{

Vedclass · Accepted Answer

v = $30$ cm,Real,Inverted,$4$ cm

Vedclass · Answer

(A) Given: Object height $O = 2.0 	ext{ cm}$,Focal length $f = +10 	ext{ cm}$,Object distance $u = -15 	ext{ cm}$.Using the lens formula $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{10} + \frac{1}{-15} = \frac{3 - 2}{30} = \frac{1}{30}$.Therefore,$v = +30 	ext{ cm}$. The positive sign indicates the image is formed on the other side of the lens.Magnification $m = \frac{v}{u} = \frac{I}{O}$.$I = \frac{v}{u} 	imes O = \frac{30}{-15} 	imes 2.0 = -4 	ext{ cm}$.The image is real,inverted,and $4 	ext{ cm}$ tall,formed at a distance of $30 	ext{ cm}$ from the lens.

$A$ $2.0 \text{ cm}$ tall object is placed perpendicular to the principal axis of a convex lens of focal length $10 \text{ cm}$. The distance of the object from the lens is $15 \text{ cm}$. Find the position,nature,and size of the image formed.

Similar Questions

Zaheen uses a convex lens to make sunlight burn a hole in a piece of card. Zaheen changes the lens in the holder for another lens with twice the power. What will she have to do to focus the sunlight on the card?

What kind of image is formed when an object is placed between the principal focus $(F)$ and the optical center $(O)$ of a convex lens?

If the image formed by a convex lens is of the same size as that of the object,what is the position and nature of the image with respect to the lens?

How many centres of curvature does a lens have?

What happens to the image formed by a convex lens if its lower part is blackened?

Vedclass Test Series

Exam Paper Generator

Online Exam Module