$A$ $50 \,W$ bulb connected in series with a heater coil is put to an $AC$ mains. Now the bulb is replaced by a $100 \,W$ bulb. The heater output will ...........

$A$ series $AC$ circuit containing an inductor $(20\,mH),$ a capacitor $(120\,\mu F)$ and a resistor $(60\,\Omega)$ is driven by an $AC$ source of $24\,V$ and $50\,Hz.$ The energy dissipated in the circuit in $60\,s$ is

$A$ series $LCR$ circuit consists of an inductor $L$,a capacitor $C$,and a resistor $R$ connected across a source of emf $\varepsilon = \varepsilon_0 \sin \omega t$. When $\omega L = \frac{1}{\omega C}$,the current in the circuit is $I_0$. If the angular frequency of the source is changed to $\omega^{\prime}$,the current in the circuit becomes $\frac{I_0}{2}$. Then,the value of $\left|\omega^{\prime} L - \frac{1}{\omega^{\prime} C}\right|$ is

An inductor of reactance $100 \text{ } \Omega$, a capacitor of reactance $50 \text{ } \Omega$, and a resistor of resistance $50 \text{ } \Omega$ are connected in series with an $AC$ source of $10 \text{ V}$, $50 \text{ Hz}$. Average power dissipated by the circuit is (in $\text{ W}$)

The angular frequency of alternating current in an $L-C-R$ circuit is $100 \, rad/s$. The components connected are shown in the figure. Find the value of the inductance of the coil and the capacity of the condenser.

Study the circuits $(a)$ and $(b)$ shown in the figure and answer the following questions.
$(a)$ Under which conditions would the $rms$ currents in the two circuits be the same?
$(b)$ Can the $rms$ current in circuit $(b)$ be larger than that in $(a)$?