A 4, mu F capacitor is charged to 400, V and | vedclass

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(B) When a charged capacitor is connected through a resistance,the energy stored in the capacitor is dissipated as heat in the resistance.The energy s

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$0.32$

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(B) When a charged capacitor is connected through a resistance,the energy stored in the capacitor is dissipated as heat in the resistance.The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 4\, \mu F = 4 	imes 10^{-6}\, F$Potential difference $V = 400\, V$Substituting the values:$U = \frac{1}{2} 	imes (4 	imes 10^{-6}) 	imes (400)^2$$U = 2 	imes 10^{-6} 	imes 160000$$U = 2 	imes 10^{-6} 	imes 1.6 	imes 10^5$$U = 3.2 	imes 10^{-1} = 0.32\, J$.Thus,the heat produced in the resistance is $0.32\, J$.

$A$ $4\, \mu F$ capacitor is charged to $400\, V$ and then its plates are connected through a resistance. The heat produced in the resistance is ....... $J$.

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