A 60,W bulb operates on a 220,V supply. The c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The power $P$ consumed by an electrical appliance is given by the formula $P = V 	imes i$,where $V$ is the voltage and $i$ is the current.Given:

Vedclass · Accepted Answer

$3/11\,A$

Vedclass · Answer

(B) The power $P$ consumed by an electrical appliance is given by the formula $P = V 	imes i$,where $V$ is the voltage and $i$ is the current.Given: Power $P = 60\,W$ and Voltage $V = 220\,V$.Rearranging the formula to solve for current $i$: $i = \frac{P}{V}$.Substituting the given values: $i = \frac{60}{220} = \frac{6}{22} = \frac{3}{11}\,A$.Therefore,the current flowing through the bulb is $3/11\,A$.

$A$ $60\,W$ bulb operates on a $220\,V$ supply. The current flowing through the bulb is:

Similar Questions

The resistor of resistance $R$ is connected to a $25\, V$ supply and the heat produced in it is $25\, J/s$. The value of $R$ is .......... $\Omega$.

Heat produced in a wire of resistance $R$ due to current flowing at constant potential difference is proportional to

In the circuit diagram,the heat produced in resistors $R$,$2R$,and $1.5R$ are in the ratio of:

Two electric bulbs have resistances in the ratio $1 : 2$. If they are connected in parallel to a constant voltage source,the ratio of power dissipated in them will be:

If $10$ bulbs of $50\,W$ are used for $10$ hours a day,how many units of electricity will be consumed in a month ($30$ days)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module