A pi^0 meson at rest decays into 2 gamma rays | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Since the $\pi^0$ meson is initially at rest,its initial linear momentum is $0$.According to the law of conservation of linear momentum,the total

Vedclass · Accepted Answer

The two $\gamma$ rays move in opposite directions.

Vedclass · Answer

(B) Since the $\pi^0$ meson is initially at rest,its initial linear momentum is $0$.According to the law of conservation of linear momentum,the total final momentum of the system must also be $0$.Let the momenta of the two $\gamma$ rays be $\vec{p}_1$ and $\vec{p}_2$. Then,$\vec{p}_1 + \vec{p}_2 = 0$,which implies $\vec{p}_1 = -\vec{p}_2$.This indicates that the two $\gamma$ rays must move in exactly opposite directions to ensure the total momentum remains $0$.

$A$ $\pi^0$ meson at rest decays into $2$ $\gamma$ rays: $\pi^0 \to \gamma + \gamma$. Which of the following must happen?

Similar Questions

Nuclear fusion is common to the pair:

Define the multiplication factor $(k)$ in the context of a nuclear chain reaction.

What is the energy released by the fission of $1 \, g$ of $U^{235}$?

The binding energy per nucleon of ${}_3^7Li$ and ${}_2^4He$ nuclei are $5.60 \, MeV$ and $7.06 \, MeV$, respectively. In the nuclear reaction ${}_3^7Li + {}_1^1H \to 2 \, {}_2^4He + Q$, the value of energy $Q$ released is ............ $MeV$.

The process that mainly takes place in stars to produce energy is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module