The products $A$ and $B$ formed in the following reactions are:
$CrO_2Cl_2 + 4NaOH \rightarrow A + 2NaCl + 2H_2O$
$A + 2HCl + 2H_2O_2 \rightarrow B + 3H_2O$

  • A
    $A = Na_2CrO_4, B = CrO_5$
  • B
    $A = Na_2Cr_2O_4, B = CrO_4$
  • C
    $A = Na_2Cr_2O_7, B = CrO_3$
  • D
    $A = Na_2Cr_2O_7, B = CrO_5$

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