An antenna current of an AM broadcast transmi | vedclass

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Question

(A) The total antenna current $I_t$ in an $AM$ transmitter is given by the formula: $I_t = I_c \sqrt{1 + \frac{m_a^2}{2}}$,where $I_c$ is the carrier

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$10.35$

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(A) The total antenna current $I_t$ in an $AM$ transmitter is given by the formula: $I_t = I_c \sqrt{1 + \frac{m_a^2}{2}}$,where $I_c$ is the carrier current and $m_a$ is the modulation index.Given: $I_t = 11\, A$ and $m_a = 50\% = 0.5$.Substituting the values into the formula:$11 = I_c \sqrt{1 + \frac{(0.5)^2}{2}}$$11 = I_c \sqrt{1 + \frac{0.25}{2}}$$11 = I_c \sqrt{1 + 0.125}$$11 = I_c \sqrt{1.125}$$11 = I_c 	imes 1.06066$$I_c = \frac{11}{1.06066} \approx 10.37\, A$.Rounding to the nearest provided option,the carrier current is $10.35\, A$.

List-$I$ (Layer of atmosphere)	List-$II$ (Approximate height over earth's surface)
$(A)$ $F_1$-Layer	$(I)$ $10\,km$
$(B)$ $D$-Layer	$(II)$ $170-190\,km$
$(C)$ Troposphere	$(III)$ $100\,km$
$(D)$ $E$-Layer	$(IV)$ $65-75\,km$

An antenna current of an $AM$ broadcast transmitter modulated by $50\%$ is $11\, A$. The carrier current is.........$A$.

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