$A$ bag $X$ contains $2$ white and $3$ black balls and another bag $Y$ contains $4$ white and $2$ black balls. One bag is selected at random and a ball is drawn from it. Then the probability for the ball chosen to be white is

  • A
    $\frac{2}{15}$
  • B
    $\frac{7}{15}$
  • C
    $\frac{8}{15}$
  • D
    $\frac{14}{15}$

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