A bag contains 4 white,5 black,and 6 red ball | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Total number of balls in the bag $= 4 + 5 + 6 = 15$.Number of white balls $= 4$.Number of red balls $= 6$.Since the events of drawing a white ball

Vedclass · Accepted Answer

$\frac{2}{3}$

Vedclass · Answer

(D) Total number of balls in the bag $= 4 + 5 + 6 = 15$.Number of white balls $= 4$.Number of red balls $= 6$.Since the events of drawing a white ball and a red ball are mutually exclusive,the probability of drawing either a white or a red ball is the sum of their individual probabilities.Probability of drawing a white ball $P(W) = \frac{4}{15}$.Probability of drawing a red ball $P(R) = \frac{6}{15}$.Probability (white or red) $= P(W) + P(R) = \frac{4}{15} + \frac{6}{15} = \frac{10}{15} = \frac{2}{3}$.

$A$ bag contains $4$ white,$5$ black,and $6$ red balls. If a ball is drawn at random,what is the probability that the drawn ball is either white or red?

Similar Questions

If $A$ and $B$ are two independent events,then $A$ and $\bar B$ are

If in a lottery there are $5$ prizes and $20$ blanks,then the probability of getting a prize is

$1$ bag contains $4$ white and $2$ black balls. Another bag contains $3$ white and $5$ black balls. If $1$ ball is drawn from each bag,find the probability that both balls are black.

$A$ bag contains $3$ white,$3$ black,and $2$ red balls. Three balls are drawn one by one without replacement. The probability that the third ball is red is:

$2$ dice are thrown. Find the probability of getting an odd number as the sum.

Vedclass Test Series

Exam Paper Generator

Online Exam Module